From 6fee85ccbc76e8aeba43dc120c5fa3c5409a4e2c Mon Sep 17 00:00:00 2001 From: Brendan Jackman Date: Thu, 5 Oct 2017 12:45:15 +0100 Subject: sched/fair: Fix usage of find_idlest_group() when no groups are allowed When 'p' is not allowed on any of the CPUs in the sched_domain, we currently return NULL from find_idlest_group(), and pointlessly continue the search on lower sched_domain levels (where 'p' is also not allowed) before returning prev_cpu regardless (as we have not updated new_cpu). Add an explicit check for this case, and add a comment to find_idlest_group(). Now when find_idlest_group() returns NULL, it always means that the local group is allowed and idlest. Signed-off-by: Brendan Jackman Signed-off-by: Peter Zijlstra (Intel) Reviewed-by: Vincent Guittot Reviewed-by: Josef Bacik Cc: Dietmar Eggemann Cc: Josef Bacik Cc: Linus Torvalds Cc: Mike Galbraith Cc: Morten Rasmussen Cc: Peter Zijlstra Cc: Thomas Gleixner Link: http://lkml.kernel.org/r/20171005114516.18617-5-brendan.jackman@arm.com Signed-off-by: Ingo Molnar --- kernel/sched/fair.c | 5 +++++ 1 file changed, 5 insertions(+) (limited to 'kernel') diff --git a/kernel/sched/fair.c b/kernel/sched/fair.c index cca1835efa7b..ed80d6bd76c8 100644 --- a/kernel/sched/fair.c +++ b/kernel/sched/fair.c @@ -5730,6 +5730,8 @@ static unsigned long capacity_spare_wake(int cpu, struct task_struct *p) /* * find_idlest_group finds and returns the least busy CPU group within the * domain. + * + * Assumes p is allowed on at least one CPU in sd. */ static struct sched_group * find_idlest_group(struct sched_domain *sd, struct task_struct *p, @@ -5917,6 +5919,9 @@ static inline int find_idlest_cpu(struct sched_domain *sd, struct task_struct *p { int new_cpu = prev_cpu; + if (!cpumask_intersects(sched_domain_span(sd), &p->cpus_allowed)) + return prev_cpu; + while (sd) { struct sched_group *group; struct sched_domain *tmp; -- cgit