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#!/usr/bin/python
'''
Print which bits are set in a value.
'''
from __future__ import print_function, division, unicode_literals
import argparse
def intdh(s):
if s.startswith("0x"):
return int(s[2:], 16)
else:
return int(s)
parser = argparse.ArgumentParser(description='Print which bits are set.')
parser.add_argument('value', metavar='VALUE')
parser.add_argument('-i', dest='invert', default=False, action='store_const', const=True)
parser.add_argument('-b', dest='bits', default=32, type=int)
args = parser.parse_args()
value = intdh(args.value)
if args.invert:
value ^= (1<<args.bits)-1
bit = 0
all_set = []
while value > 0:
if value & (1<<bit):
all_set.append('%i' % bit)
value &= ~(1<<bit)
bit += 1
print(' '.join(all_set))
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