diff options
| author | Tariq Toukan <tariqt@nvidia.com> | 2021-01-14 17:12:15 +0200 |
|---|---|---|
| committer | Jakub Kicinski <kuba@kernel.org> | 2021-01-14 10:56:13 -0800 |
| commit | 25537d71e2d007faf42a244a75e5a2bb7c356234 (patch) | |
| tree | a04271701dbbc6e074246a0a974e8555fbbf9a6e /Documentation/networking/tls-offload.rst | |
| parent | 70db767fb33adab1e7d99908c4473b5a4ca29b34 (diff) | |
net: Allow NETIF_F_HW_TLS_TX if IP_CSUM && IPV6_CSUM
Cited patch below blocked the TLS TX device offload unless HW_CSUM
is set. This broke devices that use IP_CSUM && IP6_CSUM.
Here we fix it.
Note that the single HW_TLS_TX feature flag indicates support for
both IPv4/6, hence it should still be disabled in case only one of
(IP_CSUM | IPV6_CSUM) is set.
Fixes: ae0b04b238e2 ("net: Disable NETIF_F_HW_TLS_TX when HW_CSUM is disabled")
Signed-off-by: Tariq Toukan <tariqt@nvidia.com>
Reported-by: Rohit Maheshwari <rohitm@chelsio.com>
Reviewed-by: Maxim Mikityanskiy <maximmi@mellanox.com>
Link: https://lore.kernel.org/r/20210114151215.7061-1-tariqt@nvidia.com
Signed-off-by: Jakub Kicinski <kuba@kernel.org>
Diffstat (limited to 'Documentation/networking/tls-offload.rst')
| -rw-r--r-- | Documentation/networking/tls-offload.rst | 2 |
1 files changed, 1 insertions, 1 deletions
diff --git a/Documentation/networking/tls-offload.rst b/Documentation/networking/tls-offload.rst index 0f55c6d540f9..9af3334d9ad0 100644 --- a/Documentation/networking/tls-offload.rst +++ b/Documentation/networking/tls-offload.rst @@ -530,7 +530,7 @@ TLS device feature flags only control adding of new TLS connection offloads, old connections will remain active after flags are cleared. TLS encryption cannot be offloaded to devices without checksum calculation -offload. Hence, TLS TX device feature flag requires NETIF_F_HW_CSUM being set. +offload. Hence, TLS TX device feature flag requires TX csum offload being set. Disabling the latter implies clearing the former. Disabling TX checksum offload should not affect old connections, and drivers should make sure checksum calculation does not break for them. |